L\u00f4 xi\u00ean l\u00e0 g\u00ec?<\/span><\/h2>\nL\u00f4 xi\u00ean b\u1ea3n ch\u1ea5t c\u0169ng l\u00e0 s\u1ed1 l\u00f4 \u0111\u1ec1 th\u00f4ng d\u1ee5ng nh\u01b0 ch\u00fang ta ch\u01a1i l\u00f4 : L\u1ea5y 2 ch\u1eef s\u1ed1 cu\u1ed1i \u1edf c\u00e1c gi\u1ea3i (g\u1ed3m c\u1ea3 gi\u1ea3i \u0110B)<\/p>\n
\n- x\u1ed5 s\u1ed1 MB hi\u1ec7n nay g\u1ed3m 27 gi\u1ea3i l\u00f4<\/li>\n
- x\u1ed5 s\u1ed1 mi\u1ec1n trung, MN c\u00f3 18 gi\u1ea3i l\u00f4<\/li>\n<\/ul>\n
L\u00f4 xi\u00ean, hay l\u00e0 l\u00f4 x\u00e2u l\u00e0 m\u1ed9t xi\u00ean ho\u1eb7c m\u1ed9t x\u00e2u k\u1ebft h\u1ee3p t\u1eeb 2, 3 hay 4 s\u1ed1 l\u00f4. Anh em \u0111\u00e1nh s\u1ed1 l\u00f4 xi\u00ean 2, ngh\u0129a l\u00e0 anh em c\u01b0\u1ee3c c\u00f9ng m\u1ed9t l\u00fac kqxs s\u1ebd xu\u1ea5t hi\u1ec7n c\u1ea3 2 s\u1ed1 anh em c\u01b0\u1ee3c.<\/p>\n
<\/p>\n
L\u00f4 xi\u00ean 2 con<\/strong><\/span><\/h3>\nCh\u1ecdn 2 s\u1ed1 l\u00f4, m\u1ed7i s\u1ed1 c\u00f3 2 ch\u1eef s\u1ed1 t\u1eeb 00 t\u1edbi 99<\/p>\n
C\u00e1ch d\u00f2 tr\u00fang l\u00f4 xi\u00ean 2: d\u1ef1a theo 2 ch\u1eef s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a to\u00e0n b\u1ed9 nh\u1eefng gi\u1ea3i th\u01b0\u1edfng (27 l\u00f4 gi\u1ea3i c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i, 18 l\u00f4 gi\u1ea3i c\u1ee7a c\u00e1c \u0111\u00e0i mi\u1ec1n trung v\u00e0 mi\u1ec1n nam).<\/p>\n
C\u1ea3 2 s\u1ed1 l\u00f4 n\u00e0y ph\u1ea3i gi\u1ed1ng v\u1edbi s\u1ed1 l\u00f4 anh em ch\u1ecdn.<\/p>\n
V\u00ed d\u1ee5: l\u00f4 xi\u00ean 2: 20 \u2013 02 c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i. Hay l\u00f4 xi\u00ean 2: 52 \u2013 59 c\u1ee7a \u0111\u00e0i HCM<\/p>\n
V\u1edbi t\u1ef7 l\u1ec7 l\u00f4 xi\u00ean 2 l\u00e0 1 th\u1eafng 10 th\u00ec tr\u01b0\u1eddng h\u1ee3p b\u1ea1n \u0111\u00e1nh 100.000 \u0111\u1ed3ng b\u1ea1n s\u1ebd tr\u00fang \u0111\u01b0\u1ee3c 100.000 x 10 = 1000.000 VN\u0110<\/p>\n
L\u00f4 xi\u00ean 3 s\u1ed1<\/strong><\/span><\/h3>\nCh\u1ecdn 3 con l\u00f4, m\u1ed7i s\u1ed1 c\u00f3 2 ch\u1eef s\u1ed1 t\u1eeb 00 t\u1edbi 99<\/p>\n
C\u00e1ch d\u00f2 tr\u00fang l\u00f4 xi\u00ean 3: d\u1ef1a theo 2 ch\u1eef s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c gi\u1ea3i th\u01b0\u1edfng (27 l\u00f4 gi\u1ea3i c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i, 18 l\u00f4 gi\u1ea3i c\u1ee7a c\u00e1c \u0111\u00e0i MT v\u00e0 mi\u1ec1n nam).<\/p>\n
C\u1ea3 3 con l\u00f4 n\u00e0y ph\u1ea3i tr\u00f9ng v\u1edbi con l\u00f4 b\u1ea1n ch\u1ecdn.<\/p>\n
V\u00ed d\u1ee5: l\u00f4 xi\u00ean 3: 20 \u2013 02 \u2013 04 c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i. Hay l\u00f4 xi\u00ean 3: 52 \u2013 59 \u2013 69 c\u1ee7a \u0111\u00e0i HCM<\/p>\n
V\u1edbi t\u1ef7 l\u1ec7 l\u00f4 xi\u00ean 3 l\u00e0 1 tr\u00fang 40 th\u00ec tr\u01b0\u1eddng h\u1ee3p b\u1ea1n \u0111\u00e1nh 50.000 \u0111\u1ed3ng b\u1ea1n s\u1ebd \u0103n \u0111\u01b0\u1ee3c 50.000 x 40 = 2.000.000 VND<\/p>\n
<\/p>\n
L\u00f4 xi\u00ean 4 con<\/strong><\/span><\/h3>\nCh\u1ecdn 4 s\u1ed1 l\u00f4, m\u1ed7i con c\u00f3 2 ch\u1eef s\u1ed1 t\u1eeb 00 t\u1edbi 99<\/p>\n
C\u00e1ch d\u00f2 \u0103n l\u00f4 xi\u00ean 4: d\u1ef1a theo 2 ch\u1eef s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a to\u00e0n b\u1ed9 nh\u1eefng gi\u1ea3i th\u01b0\u1edfng (27 l\u00f4 gi\u1ea3i c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i, 18 l\u00f4 gi\u1ea3i c\u1ee7a c\u00e1c \u0111\u00e0i mi\u1ec1n trung v\u00e0 MN).<\/p>\n
C\u1ea3 4 con l\u00f4 n\u00e0y ph\u1ea3i tr\u00f9ng v\u1edbi s\u1ed1 l\u00f4 b\u1ea1n ch\u1ecdn.<\/p>\n
V\u00ed d\u1ee5: l\u00f4 xi\u00ean 4: 20 \u2013 02 \u2013 04 \u2013 40 c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i. Hay l\u00f4 xi\u00ean 4: 52 \u2013 59 \u2013 69 \u2013 70 c\u1ee7a \u0111\u00e0i HCM<\/p>\n
V\u1edbi t\u1ef7 l\u1ec7 l\u00f4 xi\u00ean 4 l\u00e0 1 \u0103n 100 th\u00ec n\u1ebfu b\u1ea1n ch\u01a1i 100.000 \u0111\u1ed3ng b\u1ea1n s\u1ebd \u0103n \u0111\u01b0\u1ee3c 100.000 x 100 = 10.000.000 \u0111\u1ed3ng.<\/p>\n<\/div>\n<\/div>\n<\/article>\n<\/div>\n<\/div>\n<\/div>\n
s\u1ed1 mi\u1ec1n b\u1eafc chu\u1ea9n<\/h3>\n
L\u00f4 xi\u00ean, hay l\u00e0 l\u00f4 x\u00e2u l\u00e0 m\u1ed9t xi\u00ean ho\u1eb7c m\u1ed9t x\u00e2u k\u1ebft h\u1ee3p t\u1eeb 2, 3 hay 4 s\u1ed1 l\u00f4. Anh em \u0111\u00e1nh s\u1ed1 l\u00f4 xi\u00ean 2, ngh\u0129a l\u00e0 anh em c\u01b0\u1ee3c c\u00f9ng m\u1ed9t l\u00fac kqxs s\u1ebd xu\u1ea5t hi\u1ec7n c\u1ea3 2 s\u1ed1 anh em c\u01b0\u1ee3c.<\/p>\n
<\/p>\n
L\u00f4 xi\u00ean 2 con<\/strong><\/span><\/h3>\nCh\u1ecdn 2 s\u1ed1 l\u00f4, m\u1ed7i s\u1ed1 c\u00f3 2 ch\u1eef s\u1ed1 t\u1eeb 00 t\u1edbi 99<\/p>\n
C\u00e1ch d\u00f2 tr\u00fang l\u00f4 xi\u00ean 2: d\u1ef1a theo 2 ch\u1eef s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a to\u00e0n b\u1ed9 nh\u1eefng gi\u1ea3i th\u01b0\u1edfng (27 l\u00f4 gi\u1ea3i c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i, 18 l\u00f4 gi\u1ea3i c\u1ee7a c\u00e1c \u0111\u00e0i mi\u1ec1n trung v\u00e0 mi\u1ec1n nam).<\/p>\n
C\u1ea3 2 s\u1ed1 l\u00f4 n\u00e0y ph\u1ea3i gi\u1ed1ng v\u1edbi s\u1ed1 l\u00f4 anh em ch\u1ecdn.<\/p>\n
V\u00ed d\u1ee5: l\u00f4 xi\u00ean 2: 20 \u2013 02 c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i. Hay l\u00f4 xi\u00ean 2: 52 \u2013 59 c\u1ee7a \u0111\u00e0i HCM<\/p>\n
V\u1edbi t\u1ef7 l\u1ec7 l\u00f4 xi\u00ean 2 l\u00e0 1 th\u1eafng 10 th\u00ec tr\u01b0\u1eddng h\u1ee3p b\u1ea1n \u0111\u00e1nh 100.000 \u0111\u1ed3ng b\u1ea1n s\u1ebd tr\u00fang \u0111\u01b0\u1ee3c 100.000 x 10 = 1000.000 VN\u0110<\/p>\n
L\u00f4 xi\u00ean 3 s\u1ed1<\/strong><\/span><\/h3>\nCh\u1ecdn 3 con l\u00f4, m\u1ed7i s\u1ed1 c\u00f3 2 ch\u1eef s\u1ed1 t\u1eeb 00 t\u1edbi 99<\/p>\n
C\u00e1ch d\u00f2 tr\u00fang l\u00f4 xi\u00ean 3: d\u1ef1a theo 2 ch\u1eef s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c gi\u1ea3i th\u01b0\u1edfng (27 l\u00f4 gi\u1ea3i c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i, 18 l\u00f4 gi\u1ea3i c\u1ee7a c\u00e1c \u0111\u00e0i MT v\u00e0 mi\u1ec1n nam).<\/p>\n
C\u1ea3 3 con l\u00f4 n\u00e0y ph\u1ea3i tr\u00f9ng v\u1edbi con l\u00f4 b\u1ea1n ch\u1ecdn.<\/p>\n
V\u00ed d\u1ee5: l\u00f4 xi\u00ean 3: 20 \u2013 02 \u2013 04 c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i. Hay l\u00f4 xi\u00ean 3: 52 \u2013 59 \u2013 69 c\u1ee7a \u0111\u00e0i HCM<\/p>\n
V\u1edbi t\u1ef7 l\u1ec7 l\u00f4 xi\u00ean 3 l\u00e0 1 tr\u00fang 40 th\u00ec tr\u01b0\u1eddng h\u1ee3p b\u1ea1n \u0111\u00e1nh 50.000 \u0111\u1ed3ng b\u1ea1n s\u1ebd \u0103n \u0111\u01b0\u1ee3c 50.000 x 40 = 2.000.000 VND<\/p>\n
<\/p>\n
L\u00f4 xi\u00ean 4 con<\/strong><\/span><\/h3>\nCh\u1ecdn 4 s\u1ed1 l\u00f4, m\u1ed7i con c\u00f3 2 ch\u1eef s\u1ed1 t\u1eeb 00 t\u1edbi 99<\/p>\n
C\u00e1ch d\u00f2 \u0103n l\u00f4 xi\u00ean 4: d\u1ef1a theo 2 ch\u1eef s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a to\u00e0n b\u1ed9 nh\u1eefng gi\u1ea3i th\u01b0\u1edfng (27 l\u00f4 gi\u1ea3i c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i, 18 l\u00f4 gi\u1ea3i c\u1ee7a c\u00e1c \u0111\u00e0i mi\u1ec1n trung v\u00e0 MN).<\/p>\n
C\u1ea3 4 con l\u00f4 n\u00e0y ph\u1ea3i tr\u00f9ng v\u1edbi s\u1ed1 l\u00f4 b\u1ea1n ch\u1ecdn.<\/p>\n
V\u00ed d\u1ee5: l\u00f4 xi\u00ean 4: 20 \u2013 02 \u2013 04 \u2013 40 c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i. Hay l\u00f4 xi\u00ean 4: 52 \u2013 59 \u2013 69 \u2013 70 c\u1ee7a \u0111\u00e0i HCM<\/p>\n
V\u1edbi t\u1ef7 l\u1ec7 l\u00f4 xi\u00ean 4 l\u00e0 1 \u0103n 100 th\u00ec n\u1ebfu b\u1ea1n ch\u01a1i 100.000 \u0111\u1ed3ng b\u1ea1n s\u1ebd \u0103n \u0111\u01b0\u1ee3c 100.000 x 100 = 10.000.000 \u0111\u1ed3ng.<\/p>\n<\/div>\n<\/div>\n<\/article>\n<\/div>\n<\/div>\n<\/div>\n
s\u1ed1 mi\u1ec1n b\u1eafc chu\u1ea9n<\/h3>\n
Ch\u1ecdn 3 con l\u00f4, m\u1ed7i s\u1ed1 c\u00f3 2 ch\u1eef s\u1ed1 t\u1eeb 00 t\u1edbi 99<\/p>\n
C\u00e1ch d\u00f2 tr\u00fang l\u00f4 xi\u00ean 3: d\u1ef1a theo 2 ch\u1eef s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c gi\u1ea3i th\u01b0\u1edfng (27 l\u00f4 gi\u1ea3i c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i, 18 l\u00f4 gi\u1ea3i c\u1ee7a c\u00e1c \u0111\u00e0i MT v\u00e0 mi\u1ec1n nam).<\/p>\n
C\u1ea3 3 con l\u00f4 n\u00e0y ph\u1ea3i tr\u00f9ng v\u1edbi con l\u00f4 b\u1ea1n ch\u1ecdn.<\/p>\n
V\u00ed d\u1ee5: l\u00f4 xi\u00ean 3: 20 \u2013 02 \u2013 04 c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i. Hay l\u00f4 xi\u00ean 3: 52 \u2013 59 \u2013 69 c\u1ee7a \u0111\u00e0i HCM<\/p>\n
V\u1edbi t\u1ef7 l\u1ec7 l\u00f4 xi\u00ean 3 l\u00e0 1 tr\u00fang 40 th\u00ec tr\u01b0\u1eddng h\u1ee3p b\u1ea1n \u0111\u00e1nh 50.000 \u0111\u1ed3ng b\u1ea1n s\u1ebd \u0103n \u0111\u01b0\u1ee3c 50.000 x 40 = 2.000.000 VND<\/p>\n
<\/p>\n